Solution
Angle BAC ---- (180 – 36) degrees divided 2 = 72 degrees
Angle EDG ----- 72 degrees
Angle DEF ----- (180 – 72) degrees = 108 degrees (Answer)
Friday, April 10, 2009
Rosyth Sch 2006 PSLE Math Prelim Q41
In the figure below, AB is parallel to DE and ACDG is parallel to EF. ABC is an isosceles triangle with Angle ABC = 36 degrees. Find Angle DEF.
Solution
Angle BAC ---- (180 – 36) degrees divided 2 = 72 degrees
Angle EDG ----- 72 degrees
Angle DEF ----- (180 – 72) degrees = 108 degrees (Answer)
Solution
Angle BAC ---- (180 – 36) degrees divided 2 = 72 degrees
Angle EDG ----- 72 degrees
Angle DEF ----- (180 – 72) degrees = 108 degrees (Answer)
Hi,
ReplyDeleteI have been wondering who could be the setter for this question.
Base on what i have observed at the figure, i have notice that the figure has a flawed.
How can angle BAC = angle BCA when
angle BAC is more than angle BAC at first glance.
Hi,
ReplyDeleteI have been wondering who could be the setter for this question.
Base on what i have observed at the figure, i have notice that the figure has a flawed.
How can angle BAC = angle BCA when
angle BAC is more than angle BCA at first glance.
Why is angle EDG 72 degrees?
ReplyDeleteAngle BAC is 72 deg
ReplyDeleteAB and DE are parallel lines
ACDG is a straight line.
Therefore,
Angle BAC = Angel EDG = 72 deg
(corresponding angles)