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Monday, March 28, 2011

Math Problem Sum again

To all,
Posted through email from a reader
Please feel free to put up your working and answer
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David and Michael drove from town A to town B at different speeds. Both did not change their speeds throughout their journeys. David started his journey 30 mins earlier thatn micheal. however, micheal reached town B 5o mins earlier than david. when micheal reached town B, david had travelled 4/5 of the journey and was 75 km away from town B.

what was the distance between town a and b?
hown many kilometers did david travel in 1 hour?
what was the time taken by micheal to travel from town a to b?

sry to disturb u again but i really need help cause i dont have tuition at home.
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3 comments:

  1. Distance between Town A and B=75x5
    =375km

    David's speed=(60/50)x75
    = 90 km/h
    Therefore in 1 hour, he travelled 90 km.

    Total time taken by David=375/90
    =4 1/6 hr
    Therefore time taken by Michael
    =4 1/6hr - 80 min
    = 2hr 50 min

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  2. Do you have terms and conditions for this page? do you mind me using the questions on this page to help teach a child tuition?

    ReplyDelete
  3. a)1/5-75km
    5/5-375km
    b)50/60=5/6
    5/6*75km=62.5km/h
    c)375/62.5=6h
    50min+30min=80min
    =1h20min
    6h-1h20min=4h40min

    ReplyDelete