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Wednesday, April 14, 2010
CHIJ St Nicholas Girls' Sch 2009 P6 SA1 Paper 2 Q6
ABE is an isosceles triangle and BCDE is a rhombus. AED is a straight linie. Given that Angle ECG = 16 degrees, find Angle GCD.
Solution
Ange BEA --> (180 - 33) divided by 2 = 73.5
Angle BED --> 180 - 73.5 = 106.5
Angle CED --> 106.5 divided by 2 = 53.25
Angle ECD = Angle CED = 53.5
Angle GCD = 53.25 - 16 = 37.25
Answer: 37.25 degrees
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