ABDE is a parallelogram and BCD is an isosceles triangle. Calculate
a) Angle DBC
b) Angle EAB
The figure below is not drawn to scale.
Solution
a) Angle DBC ----- (180 – 42 – 42) degrees = 96 degrees (Answer)
b) Angle EAB = Angle EDB -----
(96 + 42) degrees = 138 degrees (Answer)
This blog is managed by Song Hock Chye, author of Improve Your Thinking Skills in Maths (P1-P3 series), which is published and distributed by EPH.
Wednesday, March 18, 2009
Tao Nan School P5 SA2 2006 Math Q44
Labels:
Geometry,
Mathematics
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