I received another request through email from a reader. Anyone willing to help her out?
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Alice, Barbie,Cora and Daylia are given some stickers. The number of stickers Alice has is 25% of the number of stickers the other 3 children have. The number of stickers Barbie has is a third of the number of stickers the other children have, while Cora has half of the number of stickers the other children have. If Daylia has 78 stickers, how many stickers does each of the other children have?
Thank You for taking your time to read this. I appreciate it if you could give me a solution to this problem as soon as possible.
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Saturday, March 19, 2011
Another Math Problem Sum
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A : B+C+D -> 1 : 4 -> Total 5u
B : A+C+D -> 1 : 3 -> Total 4u
C : A+B+D -> 1 : 2 -> Total 3u
LCM for 5, 4 and 3 is 60
A : B+C+D -> 12 : 48 -> Total 60u
B : A+C+D -> 15 : 45 -> Total 60u
C : A+B+D -> 20 : 40 -> Total 60u
A+B+C -> 12u+15+20u = 37u
D: 60u - 37u = 13u
1u -> 78/13 = 6
A: 12u -> 72
B: 15u -> 90
C: 20u -> 120
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