The figure below is made up of Triangle FHJ and Trapezium ABDE. Given that GB // FC and BJC is an isosceles triangle, find Angle GHB.
Solution
Angle BCF ----- 106 deg *
Angle BCJ ----- (180 – 106) deg = 74 deg **
Angle BJC ----- 74 deg #
Angle GBH ---- 74 deg *
Angle GHB ----- Angle BGF – Angle GBF ##
= (156 – 74) deg = 82 degrees (Answer)
* corresponding angles
** angles on a straight line
# base angles of isosceles triangle
## exterior angle
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Monday, February 16, 2009
Nanyang Pri Sch P6 CA1 2008 Math Q36
Labels:
Geometry,
Mathematics
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