The area of the figure ABCD is 48.5 square cm . Find the length of BE.
(Give your answer to the nearest tenth)
Solution
Area of ACD
1/2 x 18 cm x 10.4 cm = 93.6 square cm
Area of ABC
93.6 square cm - 48.5 square cm = 45.1 square cm
Area of Triangle ABC ----- 1/2 x base x height
45.1 square cm = 1/2 x 18 cm x height
height = (45.1 sq cm x 2 ) divided by18 cm
= 5.01 cm ~ 5.0 cm (to the nearest tenth)
Answer: 5.0 cm
This blog is managed by Song Hock Chye, author of Improve Your Thinking Skills in Maths (P1-P3 series), which is published and distributed by EPH.
Friday, September 25, 2009
Rosyth Sch 2007 PSLE Math Prelim Q43
Labels:
Mathematics,
Triangles
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment