Nigel had a total of 227 durians and pears. He sold half of the durians and bought another 40 pears. As a result, he had an equal number of durians and pears.
a) How many durians were there at first?
b) How many pears were there at first?
Solution
(a)
3 units --> 267
1 unit --> 267 divided by 3 = 89
(Durians) 2 units --> 2 x 89 = 178
Answer: 178 durians
(b)
(Pears) 1 unit - 40
--> 89 - 40 = 49
Answer: 49 pears
This blog is managed by Song Hock Chye, author of Improve Your Thinking Skills in Maths (P1-P3 series), which is published and distributed by EPH.
Wednesday, February 17, 2010
Nanyang Pri Sch 2009 P6 CA1 Math Paper 2 Q9
Labels:
Mathematics,
Whole Numbers
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That'Good Post.
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