ACS Primary 2009 PSLE Math Prelim Paper 2 Q2

Box X contains 6 times as many oranges as Box Y. Box Z contains 111 fewer oranges than Box X. If Box Y contains 1/3 the number of oranges in Box Z, find the total number of oranges in the 3 boxes.

Solution

X --> 6 units

Y --> 1 unit

Z --> 6 units - 111

(3x) Y --> Z (since Y contains 1/3 of Z, we need 3 of Ys to be equal to one of Z)

3 units --> 111

1 unit --> 111 divided by 3 = 37

(Total) 13 units - 111

--> (13 x 37) - 111

= 370

Answer: 370 oranges

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