At 9.30 am, Train A which was 200 m long, pulled out of Nanas Station and travelled towards Dadas Station at a uniform speed of 80 km/h. Half an hour later, Train B which was 150 m long, left Dadas Station and travelled towards Nanas Station at a uniform speed of 90 km/h.
a) How far has Train A travelled when Train B left Dadas Station?
b) The two trains met each other in a tunnel. Both trains took 15 minutes to completely travel through the tunnel. Calculate the length of the tunnel.
Solution
a)
Distance = speed x time
= 80 km/h x (1/2) hour
= 40 kmAnswer: 40 km
b)
(Train A) distance
= 80 km x (1/4) hr
= 20 km
(Train B) distance
= 90 km x (1/4) hr
= 22.5 km
Length of Tunnel
--> 20km + 22.5km - 0.2km (Train A's length) - 0.15km (Train B's length)
= 42.15 km
Answer: 42.15 km
Printer Friendly Version
No comments:
Post a Comment