ABCD is a square. AD = 48 cm. Given that DN is twice as long as NC and BM = MC, find the area of the unshaded part.
Solution
Solution
Area of Triangle ADN ----- ½ x base x height
= ½ x 32 cm x 48 cm = 768 square cm
Area of OMCN ----- 24 cm x 16 cm = 384 square cm
Total unshaded area ----- (768 + 384) square cm = 1152 square cm (Answer)
= ½ x 32 cm x 48 cm = 768 square cm
Area of OMCN ----- 24 cm x 16 cm = 384 square cm
Total unshaded area ----- (768 + 384) square cm = 1152 square cm (Answer)
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