This blog is managed by Song Hock Chye, author of Improve Your Thinking Skills in Maths (P1-P3 series), which is published and distributed by EPH.

Wednesday, April 23, 2008

Ai Tong School P5 SA1 2006 Math (Q44)



ABCD is a square. AD = 48 cm. Given that DN is twice as long as NC and BM = MC, find the area of the unshaded part.

Solution




Area of Triangle ADN ----- ½ x base x height
= ½ x 32 cm x 48 cm = 768 square cm

Area of OMCN ----- 24 cm x 16 cm = 384 square cm

Total unshaded area ----- (768 + 384) square cm = 1152 square cm (Answer)

No comments: