**John and Ken took part in a race. When Ken had completed the race in 20 minutes, John had only run 3/5 of the distance. John’s average speed for the race was 60 m/min less than Ken’s.(a) Find the distance of the race.(b) What was John’s speed in m/min?Solution**

2 units ----- 60 m/min

1 unit ----- 60 m/min divided by 2 = 30 m/min

(John’s speed) 3 units ----- 30 m/min x 3 =

**90 m/min**

Ken’s speed ----- 90 m/min + 60 m/min = 150 m/min

Total distance ----- John’s speed x time

= 150 m/min x 20 min =

**3000 m**

**Answers: (a) The total distance is 3000m. (b) John’s speed was 90 m/min.**

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