**The figure shown below is made up of a square, a rectangle and a right-angled triangle. The area of the square MNQR is 49 square cm and the area of the rectangle NOPS is 60 square cm. OP is 4 cm.(a) Find the length of MR(b) Find the length of SP(c) Find the area of the triangle PSQ**

**Solution**

**(a)**

Area of square MNQR = 49 square cm.

1 side is therefore 7 cm (7 x 7 =49)

**Answer: 7 cm**

**(b)**

Area of rectangle NOPS is 60 square cm.

60 square cm = SP x 4 cm

SP = 60 square cm divided by 4 cm = 15 cm

**Answer: 15 cm**

**(c)**

NQ = 7 cm, therefore

SQ = 7 cm – 4 cm = 3 cm

Area of triangle PSQ = ½ x base x height

= ½ x 15 cm x 3 cm

= 22.5 square cm

**Answer: 22.5 square cm**

## No comments:

Post a Comment