**In the figure below, AB is parallel to DE and ACDG is parallel to EF. ABC is an isosceles triangle with Angle ABC = 36 degrees. Find Angle DEF.****Solution**

Angle BAC ---- (180 – 36) degrees divided 2 = 72 degrees

Angle EDG ----- 72 degrees

Angle DEF ----- (180 – 72) degrees = **108 degrees (Answer)**

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## Friday, April 10, 2009

### Rosyth Sch 2006 PSLE Math Prelim Q41

Labels:
Geometry,
Mathematics

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## 4 comments:

Hi,

I have been wondering who could be the setter for this question.

Base on what i have observed at the figure, i have notice that the figure has a flawed.

How can angle BAC = angle BCA when

angle BAC is more than angle BAC at first glance.

Hi,

I have been wondering who could be the setter for this question.

Base on what i have observed at the figure, i have notice that the figure has a flawed.

How can angle BAC = angle BCA when

angle BAC is more than angle BCA at first glance.

Why is angle EDG 72 degrees?

Angle BAC is 72 deg

AB and DE are parallel lines

ACDG is a straight line.

Therefore,

Angle BAC = Angel EDG = 72 deg

(corresponding angles)

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