In the figure below, AB is parallel to DE and ACDG is parallel to EF. ABC is an isosceles triangle with Angle ABC = 36 degrees. Find Angle DEF.
Solution
Angle BAC ---- (180 – 36) degrees divided 2 = 72 degrees
Angle EDG ----- 72 degrees
Angle DEF ----- (180 – 72) degrees = 108 degrees (Answer)
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Friday, April 10, 2009
Rosyth Sch 2006 PSLE Math Prelim Q41
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2 comments:
Hi,
I have been wondering who could be the setter for this question.
Base on what i have observed at the figure, i have notice that the figure has a flawed.
How can angle BAC = angle BCA when
angle BAC is more than angle BAC at first glance.
Hi,
I have been wondering who could be the setter for this question.
Base on what i have observed at the figure, i have notice that the figure has a flawed.
How can angle BAC = angle BCA when
angle BAC is more than angle BCA at first glance.
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