This blog is managed by Song Hock Chye, author of Improve Your Thinking Skills in Maths (P1-P3 series), which is published and distributed by EPH.

## Wednesday, April 14, 2010

### CHIJ St Nicholas Girls' Sch 2009 P6 SA1 Paper 2 Q16

Ali and Minhua were playing a card game using 96 cards. In the first game, Minghua lost 1/5 of his cards to Ali. In the second game, Ali lost 1/3 of his cards to Minghua. After the second game, both boys had the same number of cards. How many cards did Ali have at first?

Solution

Before 1st game
Minghua --> 5 units
Ali --> 11 units
Total 16 units --> 96
1 unit --> 96 divided by 16 = 6
11 units --> 66

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JuyingPrimarySchoolMunBing said...

Er , i use 96 divide by 2 = 48 and then 48 divide by 2 = 24 . 24 = 1/3 of Ali Cards.24 x 3 = 72( Ali 3/3)After MingHua give Ali 1/5 cards one.Then 96 - 72 = 24 = 4/5 MingHua's cards . 24 divide by 4 x 5=30(MingHua at first )96 - 30 = 66(Ali at first).