**The figure below is made up of semicircles and quadrants. Finda) the area of Ab) the perimeter of BLeave your answer correct to 1 decimal place. **

**Solution**

**a)**

Area of unshaded semicircle (on the left of the figure above)

--> (1/2)(3.14)(3)(3)sq cm = 14.13 sq cm

Area of unshaded square (at the bottom left of the figure)

--> 6cm x 6cm = 36 sq cm

(The unshaded portion outside the shaded area B on the bottom right square, can be shifted left to form a square at the bottom left of the figure.)

Total Area of A

--> (14.13 + 36) sq cm

= 50.13 sq cm

~ 50.1 sq cm

**Answer: 50.1 sq cm**

b)

b)

Perimeter of B

--> There are 3 quadrants of radius 6cm, 1 semicircle of radius 3 cm and one straight line measuring 6 cm

--> (3/4)(2)(3.14)(6)cm + (1/2)(2)(3.14)(3)cm + 6 cm

= (28.26 + 9.42 + 6) cm

= 43.68 cm

~ 43.7 cm

Answer: 43.7 cm

Answer: 43.7 cm

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