Anglo-Chinese School (Primary) P5 SA2 2006 Math Question (Q48)

At a birthday party, Mr Chew had a bag of sweets. If each child receives 5 sweets, he is left with 6 sweets. If each child receives 7 sweets, he would be short of 4 sweets.

a) How many children are there at the party?

b) How many sweets did Mr Chew give to each child if he is left with only 1 sweet?


Solution




Q(a)

For 1 child --- if Mr Chew gives 5 sweets instead of 7, he ends up with 2 “more” sweets.

2 “more” sweets ----- 1 child

1 “more” sweet ----- 1 divided by 2 = ½

10 “more” sweets ----- ½ x 10 = 5

Answer: There were 5 children at the party.



Q(b)

If Mr Chew gave the 5 children 5 sweets, he would have 6 sweets left.

Number of sweets he has is therefore

(5 children x 5 sweets) + 6 sweets left = 31 sweets


If he is left with just 1 sweet, it means he gave away 30 sweets to the 5 children.

30 sweets divided by 5 children = 6 sweets each

Answer: He gave 6 sweets each.