**In the figure below, O is the centre of the circle. ABCD is a square and OD is 14 cm. Quadrant OAC is equal to Quadrant BAC. ****Find the area of the shaded parts. **

**Solution**

Reconfiguring the figure ….

**Angle EOC**----- Angle FOC + Angle FOE

= 90 degrees + 45 degrees

= 135 degrees

Area of EOC is therefore ----

135 degrees divided by 360 degrees ---

**3/8 of whole circle**

**Shaded area of circle is**

Area of whole circle – Area of EOC – Area of Triangle AOC

(22/7)(14)(14) square cm – (3/8)(22/7)(14)(14) square cm – (1/2)(14)(14) square cm

= (616 – 231 – 98) square cm

=

**287 square cm**

**Answer: The shaded area is 287 square cm.**

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