In the figure below, O is the centre of the circle. ABCD is a square and OD is 14 cm. Quadrant OAC is equal to Quadrant BAC. Find the area of the shaded parts. 
Solution
Reconfiguring the figure ….
Angle EOC ----- Angle FOC + Angle FOE
= 90 degrees + 45 degrees
= 135 degrees
Area of EOC is therefore ----
135 degrees divided by 360 degrees --- 3/8 of whole circle
Shaded area of circle is
Area of whole circle – Area of EOC – Area of Triangle AOC
(22/7)(14)(14) square cm – (3/8)(22/7)(14)(14) square cm – (1/2)(14)(14) square cm
= (616 – 231 – 98) square cm
= 287 square cm
Answer: The shaded area is 287 square cm.
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