MGS (Paya Lebar) Primary School P6 Math CA1 2006 (Q36)

Linda paid $36.40 for 8 chocolate cakes and 14 muffins. The total cost of a chocolate cake and a muffin was $3.80. Leroy brought 2 chocolate cakes and 6 muffins. How much change would he receive if he paid the cashier $30?

Solution

1 cake + 1 muffin ----- $3.80

Therefore,

8 cakes + 8 muffins ---- $3.80 x 8 = $30.40

(Linda) 8 cakes + 14 muffins ----- $36.40

(8 cakes + 14 muffins) – (8 cakes + 8muffins) ----- $36.40 - $30.40

6 muffins ----- $6

1 muffin ----- $6 divided by 6 = $1

Cake therefore cost

1 cake + 1 muffin ($1) ----- $3.80

1 cake ----- $3.80 - $1 = $2.80


(Leroy) 2 cakes + 6 muffins ----- (2 x $2.80) + (6 x $1)

= $5.60 + $6 = $11.60

Change he received

$30 - $11.60 = $18.40

Answer: He received $18.40 change.